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> Problem with the two slit experiment, Observing later
jal
Posted: Dec 19 2006, 07:47 PM


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Laserlight!
QUOTE
I can assure you that RGB color mixing is used on color CRT TV's to generate
colors. Same with a CRT color monitor. Rear projection TV's use 3 color
tubes R, G, B to project and mix all colors on the screen.

My understanding is that TRoc's approach won't change that.
QUOTE
Not at all. There is a reaction "mixing zone" just at the exit of the slit cavities.
The results of that mixing spreads and overlaps from that location.

That's a situation that I hope will be addressed by TRoc's approach.
The math has to stay valid.
Axiously waiting for TRoc smile.gif
jal


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TRoc
Posted: Dec 19 2006, 08:00 PM


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Hi all,


WELL NOW! I think everyone needed a little break from the norm. laugh.gif


Let me say just a few things, that have been misinterpreted, before I try to put together another post.

First, green is my FAVORITE color, I am NOT trying to "kill it". I am not saying it doesn't exist, just that it is not primary, from ALL frames of reference. AE warned about going too far in theorizing from a "preferred frame".

Did everyone (who doesn't have their own prism) LOOK at the un-doctored, color photographs in THIS link? http://www.scielo.br/img/revistas/ea/v7n19/encarte19.pdf

I have a hard time believing that, after seeing those photos, you would not understand what I'm saying.

The changing of the angle of diffraction REMOVES green from the rainbow (yes, LL, I've seen a few of those wink.gif ). You are left with 2 pairs of colors, red/yellow, and cyan/violet. With THESE 4 colors, ALL known colors can be produced. This is not true of ANY of the existing schemes that you all now have links to.

LL, I think if you dig DEEP into the engineering literature of color monitors, TV, printers, copiers, etc., you will find that R-B-G is NOT the complete, easiest, and/or cheapest way to get the effect of "real life" images. M-Y-C does it (with a little black) cheaper, and better. I don't have any links for this, and my memory could be wrong.

This goes back to the FACT that it TAKES some "violet" to make "violet". Now, IF you "tweak" the R-G-B spectrum into R-B-V, that would do it. Again, since this is Science, I really DON"T like it when "they" (not you, THEY) say one thing, but mean another.


GE, yes! Thanks for the links. This was just a "side-note", about the superimposed B&W photos making "full color" prints. I did glean a TELLING statement there, that seems to KEEP coming up, when I search for things that are supposed to be FUNDAMENTAL to our TOWER of Science.

http://www.greatreality.com/Color2Color.htm
QUOTE
But the interesting accident raised profound questions about the physics and physiology of color vision, and set Land off on extensive investigations of 2-color photography.  He continued to record his images using only red and green light, but experimented widely with projection colors.
..
He was ultimately able to create full-color images with only light of 579 nanometers and 599 nanometers wavelength.  We normally perceive those two specimens of light as being yellow, and almost identical in color, but two-color images viewed with those colors of light can produce the perception of reds, greens and blues.


WOW!

QUOTE
They are reminiscent of the written descriptions of J. C. Maxwell's first three-color images in 1861.  The Muser's article on Maxwell's experiments explains that Maxwell did not have the materials necessary to accomplish what he thought he was doing in his experiments.  Where Land's nineteen-fifties images didn't record any blue light, Maxwell's eighteen-sixties images couldn't have recorded any red or green light.  Yet both obtained satisfactory color reproduction.  It seems possible that their results will one day have a common explanation.


QUOTE
In The Muser's opinion, the later work lacks the simple elegance of Land's earlier inquiries.  It doesn't seem to adequately answer the questions raised in the fifties experiments.  And it doesn't tie together the loose ends of the past two centuries of color vision investigations.

We still have more questions than answers.

(emphasis added)


The other thing I need to make clear: the change in frames of reference of the observer.

The "standard" (Newton) prism experiment goes through this sequence:

SOURCE>>>SLIT---PRISM===WALL===EYE

and produces a "sturdy" (unchangeable), or fixed "rainbow".

My "twist" in the storyline goes this way:

SOURCE>>>SLIT--WALL--PRISM=EYE

and this produces a "changeable" rainbow, where you can eliminate green from the center. The PAIRS (dualistic representations of E and M components?) of colors that remain, maintain a "polar" relationship.

What this does is allow us to view the diffraction pattern, normally seen in black & white, in a "new light"; colored that is.


Finally, the diffraction grating. This is a MANY SLIT version of the DSE. From http://hyperphysics.phy-astr.gsu.edu/hbase...grating.html#c1

QUOTE
The condition for maximum intensity is the same as that for a double slit. However, angular separation of the maxima is generally much greater because the slit spacing is so small for a diffraction


yet,

QUOTE
When light of a single wavelength , like the 632.8nm red light from a helium-neon laser at left, strikes a diffraction grating it is diffracted to each side in multiple orders. Orders 1 and 2 are shown to each side of the direct beam. Different wavelengths are diffracted at different angles, according to the grating relationship.


Apparently, the laser had more than one frequency, because it was dispersed into FIVE different places on the screen. You could also say that it went to the CENTER, and 2 PAIRS of symmetric locations, or "side lobes". That way, you only have to account for THREE frequencies: the fundamental, @ 632.8nm , and two others, BOTH having some position symmetry, or steady RATIO of frequencies. The intensity also falls off away from center in this experiment.


Some experimental set ups DO NOT allow for a "changing of frame of reference", and some do. I am suggesting (just as in the photon/electron relationship) that we look at BOTH, and then COMBINE what we learned. What are the SIMILARITIES?


ciao,

T.Roc



This post has been edited by TRoc on Dec 19 2006, 08:08 PM


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Laserlight
Posted: Dec 19 2006, 08:20 PM


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TRoc,

I've worked on CRT TV's and rear projection TV's and their electronic schematics.
RGB is the standard. If you look closely at the pixels on your monitor (just
put a drop of water on the screen) you will see RGB pixels.

As for color inkjet printers Black, Cyan, magenta,
and yellow are the typical inkjet refills.

rolleyes.gif

LL


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jal
Posted: Dec 19 2006, 08:36 PM


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Good Day!
As to where the action happens .... duh.... more than one place
SOURCE>>>SLIT---PRISM===WALL===EYE
SOURCE>>>SLIT--WALL--PRISM=EYE
In the range that we are now talking about, we mean electrons changing their energy level.
jal
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This post has been edited by jal on Dec 19 2006, 08:39 PM


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Confused2
Posted: Dec 19 2006, 08:43 PM


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Hi LL et al,

I think you are suggesting the slits are firing blanks in certain directions .. ?? We could be back to definition problems here.

Using the ripple tank appplet

http://www.echalk.co.uk/Science/Physics/ri...Tank/ripple.htm

Select Double Slit
Mouse=Edit Walls

Close up the slits that the applet gave you and open new ones towards each end of the wall (mousing on a wall makes it go away).

Hopefully you see the slits firing in all directions .. the interference 'appears' afterwards.

You see it?

Thoughts? Comments?

Best wishes,

-C2.

As a point of minor interest .. I think a chap called Ashfar claimed he could put bits of wire in the null zones and it made no difference .. I'm not sure it proved anything other than that he had a very steady hand .. anyway.. one can have fun putting walls down the destructive interference lines and wondering what (if anything) it all proves.

Edit.. if you try putting walls in the interference nulls .. it might be interesting to make some comment about standing waves -

This post has been edited by Confused2 on Dec 19 2006, 08:49 PM
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TRoc
Posted: Dec 19 2006, 08:50 PM


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LL,


OK, thanks. I knew my memory was a little "fuzzy". I haven't worked on either TV's or printers, so I'll defer to your expertise.


Can you address HOW violet is produced on a TV?

Or, is there some problem with the real reproduction of that color.

I do have some expertise in WATCHING TV ! laugh.gif

From my "full time Scientific mind", I have gathered that the RECEPTION clarity (what I IMAGINE to be "reception" problem) gets kicked in the arse when my TV tries to reproduce colors in the magenta to violet range. So, my "imagination" is probably wrong, and this is not a reception (signal) problem, and the common denominator is the problematic reproduction of higher energy colors than RGB allow for (easily, or within standards).

Is the "power drop" in apparent reception clarity caused by the energy conservation inside the TV, when energy is "borrowed" from the system to reproduce these higher energy colors?


T.Roc



--------------------

I know Nothing. I looked all over to find it, but found it Nowhere. The funny thing is, it was right between 2 things, that I knew Everything about. It felt like forever, but really, it was no Time at all.

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Laserlight
Posted: Dec 19 2006, 08:55 PM


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Jal,

Talking about the DSE, the mixing takes place at/near the slit cavities. The rest
of the observed result is due to reflection and detection. IMO, there is no
mixing taking place at the screen.

TRoc,

A shadow contains no energy. The dark bands also contain no energy from
the arriving photons, they are "shadows" where no photons are falling.
The lighted bands contain energy from arriving photons. The energy of the
photons as they leave the DSE "mixing zone" determines their trajectory and
where they hit the screen.

The phase angle of the incident photons determines how they are additively
mixed and their resultant flight path toward the screen. Notice that each
lighted band has a "range" (spread) of energy. IMO, this is the phase
angle variability (uncertainty) of exactly where, in the phase angle, the
E and B field amplitude is.

biggrin.gif
LL
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Confused2
Posted: Dec 19 2006, 09:02 PM


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Hi TRoc,

If you've got microsoft 'Paint' or any graphics program .. click on custom colour (or something similar and you can find the RGB content for violet. I'm colour blind so I can't help.

Best wishes,

-C2.
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Laserlight
Posted: Dec 19 2006, 09:05 PM


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Hi TRoc,

QUOTE
Is the "power drop" in apparent reception clarity caused by the energy conservation inside the TV, when energy is "borrowed" from the system to reproduce these higher energy colors?
blink.gif blink.gif blink.gif

What? huh.gif See attached! Is your RGB monitor able to show these clearly?


User posted imageUser posted image

User posted imageUser posted image

tongue.gif
LL

This post has been edited by Laserlight on Dec 19 2006, 09:10 PM
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TRoc
Posted: Dec 19 2006, 09:21 PM


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Hi all,


OK, perfect timing.


C2's statement:
QUOTE


QUOTE (TRoc)
So, this "new energy" term, flux, falls to zero in the dark bands. But not the REAL energy, I say. The real energy term is conserved.

Looking at ..
http://www.teachspin.com/instruments/two_s..._combiplot2.gif
it looks like photons aren't counted in the dark bits .. it seems the little swines that should have been there have hopped over into the bright bits... probably not a popular move, but there it is.


and LL's statement:
QUOTE
The dark bands also contain no energy from
the arriving photons, they are "shadows" where no photons are falling.



We have found a difference in opinions, very good.

Some info from http://en.wikipedia.org/wiki/Spontaneous_emission
QUOTE
There are two different ways in which decay or relaxation can occur: radiative and nonradiative. In nonradiative relaxation, the energy is absorbed as phonons, more commonly known as heat. Nonradiative relaxation is nearly impossible to measure and cannot be inferred except in very small particles because the difference in the temperature before and after a relaxation is so small that it is in the noise of any measurement for practical systems.

(emphasis added)

That is what I said earlier. "Heat" (or phonons) has been explained statistically by the laws of thermodynamics. Now, it's NOT enough to measure, but THERE IS ENERGY being delivered to the dark bands. The "photons" were NOT "destructively" evaporated.

QUOTE
Nonradiative relaxations occur when the energy difference between the levels is very small, and these typically occur on a much faster time scale than radiative transitions.


Faster than our RADIATIVE measurements.

QUOTE
Quantum mechanics explicitly prohibits spontaneous transitions. That is, using the machinery of ordinary first-quantized quantum mechanics, if one computes the probability of spontaneous transitions from one stationary state to another, one finds that it is zero. In order to explain spontaneous transitions, quantum mechanics must be extended to a second-quantized theory, wherein the electromagnetic field is quantized at every point in space. Such a theory is known as a quantum field theory; the quantum field theory of electrons and electromagnetic fields is known as quantum electrodynamics.


However, the EM field IS ALREADY QUANTIZED, in terms of "photons", and energy.

QUOTE
In quantum electrodynamics (or QED), the electromagnetic field has a ground state, the vacuum state, which can mix with the excited stationary states of the atom. As a result of this interaction, the "stationary state" of the atom is no longer a true eigenstate of the combined system of the atom plus electromagnetic field. In particular, the electron transition from the excited state to the electronic ground state mixes with the transition of the electromagnetic field from the ground state to an excited state, a field state with one photon in it.


This is the problem of "the electromagnetic field is quantized at every point in space, .. with one photon in it". This leads to the interpretation of "free energy" in the "zero point field". This is not the "whole picture", something is obviously wrong.

QUOTE
Although there is only one electronic transition from the excited state to ground state, there are many ways in which the electromagnetic field may transition from ground state to a one-photon state. That is, the electromagnetic field has infinitely more degrees of freedom, corresponding to the directions in which the photon can move off in.


Before the FIRST act of quantization, the parameters are LIMITED. AFTER the SECOND quantization, they are INFINITE. I can not agree with this approach.


regards,

T.Roc





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I know Nothing. I looked all over to find it, but found it Nowhere. The funny thing is, it was right between 2 things, that I knew Everything about. It felt like forever, but really, it was no Time at all.

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Laserlight
Posted: Dec 19 2006, 09:24 PM


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Color bars:

Wikipedia color bars

Composite video signals:
CRT Pixels

LL
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TRoc
Posted: Dec 19 2006, 09:46 PM


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LL,


I just can't type fast enough to keep up with you !!

laugh.gif


I think we may have had a "non-conversation"; I was just talking about my TELEVISION, not my monitor.

My TV picture has MAJOR problems reproducing certain frequencies, WHILE maintaining the same quality picture.

My computer monitor has an EXTRA power source (transformer?) in the cable itself. This was not the case about 10 years ago. I think I remember a similar "loss of quality" in the OLD computer monitors, but I could be wrong.


http://en.wikipedia.org/wiki/RGB_color_model
QUOTE
The RGB color model itself does not define what is meant by ‘red’, ‘green’ and ‘blue’, and the results of mixing them are not exact unless the exact spectral make-up of the red, green and blue primaries are defined.


If the definitions of RGB are "tweaked" to include some violet (indigo, for instance), I have no problem with the effectiveness of RGB. However, AS STATED, RGB can NOT produce all colors MOST effectively.


T.Roc



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I know Nothing. I looked all over to find it, but found it Nowhere. The funny thing is, it was right between 2 things, that I knew Everything about. It felt like forever, but really, it was no Time at all.

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Laserlight
Posted: Dec 19 2006, 09:56 PM


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TRoc,

I don't want you to get the impression that we are "out to get you" laugh.gif ,
it is just that we/I am questioning your line of logic as it pertains to the
DSE experimental results. smile.gif

QUOTE
That is what I said earlier. "Heat" (or phonons) has been explained statistically by the laws of thermodynamics. Now, it's NOT enough to measure, but THERE IS ENERGY being delivered to the dark bands. The "photons" were NOT "destructively" evaporated.


HHmmmm, If you shine a flashlight beam at a wall, is there energy from the
beam hitting the wall 2 feet away from the "spot". Energy is applied at 1 general
location of the beam, areas outside of that location are not receiving photons/energy. (same with a laser)

QUOTE

This is the problem of "the electromagnetic field is quantized at every point in space, .. with one photon in it". This leads to the interpretation of "free energy" in the "zero point field". This is not the "whole picture", something is obviously wrong.


Text QUOTE 
Although there is only one electronic transition from the excited state to ground state, there are many ways in which the electromagnetic field may transition from ground state to a one-photon state. That is, the electromagnetic field has infinitely more degrees of freedom, corresponding to the directions in which the photon can move off in.

Before the FIRST act of quantization, the parameters are LIMITED. AFTER the SECOND quantization, they are INFINITE. I can not agree with this approach.


This relates perfectly to the PM on the atomic "lattice" that I sent to you last week.

Yes, the instantaneous position of the electron in its orbit is uncertain. Its
dipole relationship to the nucleus is in constant motion, so it can emit a photon
in any perpendicular direction to the dipole moment at the instant of energy
level transition to a lower level. IMO, surface photon emissions are the only ones
that couple to free space. In general, internally generated photons stimulate the atomic
matrix structure surrounding them, until they "migrate" to the "skin" of the
surface layer, where they couple to space in all directions and radiate away.

Even inside a laser, there are photons that escape thru the sides of the laser
media and are not part of the laser beam generated in the cavity between the
mirrors. There is not 100% energy coupling efficiency or lossless photon laser beam
generation. Much loss is thru heat and spurious random light leakage.

QUOTE
My TV picture has MAJOR problems reproducing certain frequencies, WHILE maintaining the same quality picture.


Time for that HDTV set that you've been eyeing??? laugh.gif

LL

This post has been edited by Laserlight on Dec 19 2006, 10:03 PM
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Confused2
Posted: Dec 19 2006, 10:00 PM


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Hi TRoc,

I think you might have found the key to Pandora's box that yquantum mentioned a while back smile.gif .

If a photon were confined to a box it would it not have have modes .. resonances .. whatever you wish to call it. Could it be that the only single mode cavity is one with no walls? .. infinite? .. still the one quantization .. just ... wacko.gif !

Best wishes,

-C2.
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jal
Posted: Dec 19 2006, 10:01 PM


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C2
Ashfar experiment controversy.
TRoc is saying that there cannot be loss of energy. Makes sense.
Does all the energy show up at the "light" spots?
I don't think TRoc is saying that. Something needs to be explained.
Comments??
jal


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