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Spring problem Need Help ASAP, Work| chazgurl4life |
 Posted: Mar 19 2006, 05:11 PM
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Newbie  Group: Members Posts: 16 Joined: 19-March 06 Positive Feedback: 0% Feedback Score: 0  |
A vertical spring (ignore its mass), whose spring stiffness constant is 900 N/m, is attached to a table and is compressed down 0.110 m.
(a) What upward speed can it give to a 0.300 kg ball when released? -----------m/s (  How high above its original position (spring compressed) will the ball fly?------m Now if im following my lecture notes correctly for part a) I am using the equation is that V^2=KX^2 ------- mass of ball so when we out it all out it should be v^2=900n/m(-.110m)^2 ----------------- .300 kg -------------------------->v=6.02 m/s but that answer is wron apparently. I dont know where im going wrong. |
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| lostinjersey |
Posted: Mar 19 2006, 06:22 PM
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Newbie Group: Members Posts: 20 Joined: 19-March 06 Positive Feedback: 0% Feedback Score: 0 |
I think the equation should be .5mv^2=kx^2
the max kinetic enrgy of the ball will be equal to the max potential energy the ball has. -------------------- www.lazyforum.net
Where reclined is a state of mind. "Empty your mind. Be formless... shapeless like water. If you put water into a cup it becomes the cup. You put water into a bottle it becomes the bottle. You put it into a teapot it becomes the teapot. Water can flow, and it can crash. Be water, my friend..." -Lee Jun Fan (aka Bruce Lee) |
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