A uniform stick 1.5 m long with a total mass of 300 g is pivoted at its center. A 4.0 g bullet is shot through the stick midway between the pivot and one end (Fig. 11-26). The bullet approaches at 250 m/s and leaves at 160 m/s. With what angular speed is the stick spinning after the collision?


I got .375 kg/m^2/s and i was wondering if you could convert that into rad/s. I solved for the angular momentum instead. Then i tried to solve for rad/s so please tell me what i did wrong
I did L=mrv with r as 1.5/2/2=.375 since the bullet is shot in the middle of the radius.

I got L1 as .375 and l2 as .24

Then i did L1-L2 which is .135

for the stick, inertia is 1/12
mL^2 which is got .3375

Then i did .135/.3375 which is .4 rad/s