in atom hydrogen to find force electricity between nucleus positive and electron negative to calculate from law coulomb : f=9*10^9*|-e|*|e|/r^2 { relation 1}
whereas e: cargo
electron and she the same cargo nucleus to be estimated in coulomb
r: to halve diameter atom hydrogen to be estimated in meter r=53*10
^-12m
but to consider relation constitution in moving : f=m*a whereas : m : mass electron to be estimated in kg
m=9.10953*10 ^-31 kg
a: acceleration electron it is possible considering
a=v^2/r considering because movement electron in perimeter nucleus approximately admissible it movement circularity regular that is f=m*v^2/r {relation 2} :v: speed turn : electron in perimeter nucleus to be estimated in m/s :v=22*10^ 5 m.s-1
from relation 1 to result:
f=9*10 ^ 9*|-e|*|e| /[53*10 ^ -12]^2 relation3
9.10953*10 ^-31*[22*10^ 5]^2/53*10^-12-12 f= relation4
frome relation 2
in compensation relation4 in relation3 to find : e^ 2 = 2.5964184*10^-38

to result : 1.6113405-* 10^-19 = e cargo
electron
or 1.6113405+*10^-19=e cargo proton