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> The Position Of An Electron At Almost The S.o.l, Heisenberg Uncertainty Principle
penmanta0711
Posted: Nov 28 2011, 09:36 PM


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No object can travel faster than the speed of light, so it
would appear evident that the uncertainty in the speed of
any object is at most 3 * 10^8 m s
(a) What is the minimum uncertainty in the position
of an electron, given that we know nothing about
its speed except that it is slower than the speed of
light?

Known
(Δx)(Δp)=h/4∏ hence Δx=h/4∏(mass of e-)(velocity)
Mass of e-=9.10x10^-31 kg
Velocity is equal to 3x10^8 m s
I plug in my values and came up with 3.049 x10^-59meters
My answer seems a bit wonky..could you double check..and if wrong give me hints to solve properly...thank you
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Edward 3
Posted: Nov 29 2011, 02:41 PM


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You appear to be using speed when you should be using momentum.
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