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| penmanta0711 |
Posted: Nov 28 2011, 09:36 PM
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Newbie ![]() Group: Members Posts: 1 Joined: 28-November 11 Positive Feedback: 0% Feedback Score: 0 |
No object can travel faster than the speed of light, so it
would appear evident that the uncertainty in the speed of any object is at most 3 * 10^8 m s (a) What is the minimum uncertainty in the position of an electron, given that we know nothing about its speed except that it is slower than the speed of light? Known (Δx)(Δp)=h/4∏ hence Δx=h/4∏(mass of e-)(velocity) Mass of e-=9.10x10^-31 kg Velocity is equal to 3x10^8 m s I plug in my values and came up with 3.049 x10^-59meters My answer seems a bit wonky..could you double check..and if wrong give me hints to solve properly...thank you |
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| Edward 3 |
Posted: Nov 29 2011, 02:41 PM
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Advanced Member ![]() ![]() ![]() ![]() ![]() Group: Power Member Posts: 849 Joined: 14-January 07 Positive Feedback: 52.31% Feedback Score: -87 |
You appear to be using speed when you should be using momentum.
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