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| DBrenchley |
Posted: Sep 30 2010, 01:57 AM
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Newbie ![]() Group: Members Posts: 3 Joined: 30-September 10 Positive Feedback: 0% Feedback Score: 0 |
Good day !
Hoping you folks maybe of assist .. need help determining formulas .. 1. Involves a pneumatic air cylinder. 1-1/16 bore 5/16 shaft double acting w/ a spring (3Lb - 6Lb) to force full extension the air inlet opposite the shaft employs a one way restriction valve (free on inlet / restricted on exhaust) there is no air supply other then atmosphere. The question is .. if the cylinder is fully compressed, and the air restriction valve is fully closed, how far will the cylinder move, until the spring force equals air pressure. 2. Involves a slider crank .. well actually a crank / crank .. a motor/crack drives a hollow cylinder. a crank is attached to a motor whose radius is equal to the radius of the cylinder attached to the crank via a rod. The rod attaches to the radius of the cylinder such that radius / crank = radius / cylinder. If the cylinder weight is 26lbs .. how much torque must the motor generate to be able to rotate the cylinder ? THANKS for any assist you might offer |
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| DBrenchley |
Posted: Sep 30 2010, 05:23 PM
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Newbie ![]() Group: Members Posts: 3 Joined: 30-September 10 Positive Feedback: 0% Feedback Score: 0 |
Gee .. if I asked for a formula for the unified force theory, bet I'd have something by know ..
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| rcgldr |
Posted: Oct 1 2010, 04:50 PM
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Newbie ![]() Group: Members Posts: 9 Joined: 1-August 10 Positive Feedback: 0% Feedback Score: 0 |
> air cylinder
Please check my math: 17/16 in bore = .53125 in radius. Cross section area = π r^2 = .886641 in^2 Pressure = force / area = 6 lbs / .886641 in^2 = 6.767 psi > rotate cylinder If there's no friction, and no limit on time to spin up to speed, then any non-zero torque will eventually spin the cylinder to some speed. |
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| Plumb Bob |
Posted: Oct 2 2010, 04:54 AM
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Member ![]() ![]() Group: Power Member Posts: 63 Joined: 30-November 09 Positive Feedback: 100% Feedback Score: 6 |
Only if you asked it in the "Burkhard Heim's Particle Structure" Cult forum where the cult followers think imagination is equal to physics. This post has been edited by Plumb Bob on Oct 2 2010, 05:01 AM |
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| DBrenchley |
Posted: Oct 2 2010, 06:16 PM
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Newbie ![]() Group: Members Posts: 3 Joined: 30-September 10 Positive Feedback: 0% Feedback Score: 0 |
THANKS RC ..
With regard to the cylinder .. p = F/pi(r1^2 - r2^2) w/ the spring fully compressed yields 1.85 psi which tells me the piston is going to move. As to how far I think is going to involve calculus .. and Boyles Law .. which is beyond my scope .. I'm thinking I will perform multiple iterations with an ever decreasing assumed value for volume .. though I'm not sure this mathematically sound .. but may get me close enough to proof concept of the mechanism. With regard to your comment on the second problem .. I'm not a physicist or a mathematician but in my universe that assumption has to be incorrect .. or am I missing something .. |
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